I blurted out:
> an entry on disk. Each entry takes about 80(?) bytes, so when you
> are using 4GB of disk, the memory usage for the object pointers/info
> will be about 32MB.
Duh! I can be rather dumb at times (no comments please). :-)
That should read. 4GB of disk at about 10K per object makes 400000
objects at 80 bytes each = 32MB memory. That is probably a worst
case figure - my average object size seems to be more around 15-20K.
As you can see it is very dependant on the size of the objects
in your cache, so do a tally of your own cache and have a look.
-Russell
Received on Thu Jun 13 1996 - 08:14:58 MDT
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